Solving Parallel Circuits Admittance Method

Solving Parallel Circuits Admittance Method

Solving Parallel Circuits Admittance Method

In this article Solving Parallel Circuits Admittance Method is explained. Admittance of a circuit is defined as the reciprocal of its impedance. Its symbol is Y.


  


Its unit is Siemens (S). A circuit having an impedance of one ohm has an admittance of one Siemens. The old unit was mho (ohm spelled backwards). As the impedance Z of a circuit has two components X and R (Figure (A)), similarly, admittance Y also has two components as shown in Figure (B). The X – component is known as conductance and Y- component as susceptance. 

Solving Parallel Circuits Admittance Method
Figure A
Solving Parallel Circuits Admittance Method
Figure B

Obviously, conductance g = Y cos φ
or 

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Similarly, susceptance 

The admittance

http://engg.mcqsduniya.in/wp-content/uploads/2021/03/Solving-Parallel-Circuits-Admittance-Method-5.jpg

 

The unit of g, b and Y is Siemens. We will regard the capacitive susceptance as positive and inductive susceptance as negative.

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Solving Parallel Circuits Admittance Method
Figure C
Application of Admittance Method


Consider the 3-branched circuit of Figure (C). Total conductance is found by merely adding the conductances of three branches. Similarly, total susceptance is found by algebraically adding the individual susceptances of different branches.


Total conductance G = g1 + g2 + g3 ………

Total susceptance B = (− b1) + (− b2) + b3 ……

(algebraic sum)

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Total current I = VY ; Power factor cos φ = G/Y

Read article – Units of Resistivity

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